x^2(x-6)=3x-4(2-x)

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Solution for x^2(x-6)=3x-4(2-x) equation: 



x^2(x-6)=3x-4(2-x)

We move all terms to the left:

x^2(x-6)-(3x-4(2-x))=0

We add all the numbers together, and all the variables

x^2(x-6)-(3x-4(-1x+2))=0



We calculate terms in parentheses: -(3x-4(-1x+2)), so:

3x-4(-1x+2)

We multiply parentheses

3x+4x-8

We add all the numbers together, and all the variables

7x-8

Back to the equation:

-(7x-8)



We get rid of parentheses

x^2(x-6)-7x+8=0

We move all terms containing x to the left, all other terms to the right

x^2(x-6)-7x=-8

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